Chemistry, asked by ankalaramanamani, 10 months ago

0.5 gram of an organic compound liberate 112 ml of
nitrogen at STP. The percentage of nitrogen in the
compoud is......​

Answers

Answered by rudraaggarwal239982
2

Answer:

here is your answer mate...

Explanation:

0.59 g of an organic compound produces 112 mL nitrogen at NTP. The percentage of nitrogen in the compound through Duma's method is. =28×112×10022400×0.59=23.7.

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