0.5 grams of iron wire was dissolved in 75 mL of h2so4 solution. And volume was increased to 250 ml with water 25 mL of this solution reducer 285 mL of n by tell kmno4 solution. The amount of pure iron present was
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Answer:
The iron is 100% pure.
Explanation:
22.90 ml 0.09672 N KMnO4 = 22.90 ml 0.09672 N FeSO4
Amount of FeSO4 in the solution = 0.3366g
Amount of iron in 0.3366g of FESO4 = 0.124g
Thus, percentage = 0.124 x 100 ÷ 0.124 = 100
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