Question

0.5 K.G piece of alluminium increases it's temperapture 7 degree celcius when heat energy is added. how much heat energy is produced this change in temperature (S=882J/KG-K)​

Answer 1

Answer:

Given : m=0.5 kg;S=800 J/kg

o

C; ΔT=10.0

o

C

Heat required to raise the temperature Q=mS(ΔT)

∴ Q=0.5×800×10.0

⟹Q=4000 J

Answer 2

Answer:

No.of moles of Al(m)=

(27gmol

−1

)

60g

= 2.22mol

2) Molar heat capacity(c) = 24Jmol

−1

K

−1

Rise in temperature ΔT= 55–35

=

20K

3) Heat evolved (q)

=

C×

m×

T

=

(24Jmol

−1

K

−1

)×

(2.22mol)×

(20K)

= 1065.7J

= 1.06kJ