Question

0.5 kg ball falls into a heap of sand from a height of 10 m above the sand. It comes to rest 2.5 m beneath the surface of the sand. What is the average force exerted on the ball by the sand.

Answer 1

m = 0.5 kg
s = 10 m + 2.5 m = 12.5 m
u = 0 m/s
g = 9.8 m/s

F= mg
F= 0.5*9.8
F= 4.9 N