Question

0.5 kg cart connected to life spring for which the first concert is 20 Newton per metre on a horizontal frictionless extra calculate the total energy of the system and the maximum speed of the cat if the amplitude of the motion is 3.0 cm​

Answer 1

Answer:

total energy=0.009 J, velocity=0.190 m/s

Explanation:

Use Hooke's law:

PE=1/2kx^2

=1/2*20*0.03^2

total energy=0.009 J

Next, use kinetic energy formula:

KE=1/2mv^2

v=sqrt(2KE/m)

=sqrt(2*.009/.5)

velocity=0.190 m/s