Question

0.5 mole of a gas at a temperature 300 Kelvin expance isothermal from an initial volume of 6 litre to 2 litre find the work done by the gas and also find the how much heat is supplied to the gas

Answer 1

Answer:

Solution: The work done in isothermal

expansion is W = nRTln

V/Vfi

Where n = 0.5, Vf

= 6L, Vi

= 2L

W = 0.5 mol

8 319 300 62K

.ln mol

K L/L

= 1.369 kJ.

(b) From the first law of thermodynamics,

the heat supplied in an isothermal process

is spent to do work an a system. Therefore,

Q = W = 1.369 kJ.