Question

0.5 mole of diatomic gas at 27 degree centigrade is heated at constant pressure so that it's volume is trebled. If R=8.3Jmole-1k-1 then work done is...

Answer 1

Answer:

The answer is 2.49 KJ.

Explanation:

Let the initial pressure is "p"

"Vi" is the initial volume.

"Vf" is the final volume.

"n" is the number of moles .

Ti is the initial pressure = 300 k

Solution:  

Work done = p(Vf - Vi)

                 = p(3Vi - Vi)

                 = 2pVi      (Since PV = nRT)

Thus,            

          W = 2 x n x R x T

              = 2 x 0.5 x 8.3 x 300 = 2.49 KJ

Thus the work done is 2.49 KJ.