Question

0.5 mole of each a and B are allowed raect if an equilibrium 0.2 moles of D are formed then the equilibrium constant for the following reaction will be :- A(g) + B(g)=C(g) + D(g)​

Answer 1

Answer:

The expression for the equilibrium constant is A+2B⇔C+2D.

The expression for the equilibrium constant is

[A][B]%2

[C][D]

2

.

The following table lists the equilibrium concentration of various species.

A

B

C D

Initial

1

2

0

0

Change

-x

-2x

x

2x

Equilibrium

1-x

2-2x

x

2x

But [C]=0.4=x.

Hence, the number of moles of A,B,C and D in 0.5 L are 06,1.2,0.4 and 0.8 respectively.

The molar concentrations of A,B,C and D are 1.2, 2.4, 0.8 and 1.6 respectively.

Substitute the values in the expression for the equilibrium constant.

K

c

=

1.2×(2.4)

2

0.8×(1.6)

2

=

27

8

.

Answer 2

Answer:

0.16 it's a answer

Explanation:

i hope you understand