Question

0.5 mole of each of H2, SO2 and CH4 are kept in a container. A hole was made in the container. After 3 hours, the order of partial pressures in the container will be

(A) pH2 > pSO2 > pCH4
(B) pH2 > pCH4 > pSO2
(C) pSO2 > pH2 > pCH4
(D) pSO2 > pCH4, > pH2

Answer 1

hola mate

option a is correct

Answer 2

The order of partial pressures in the container after 3 hours will be p$SO_2$>p$CH_4$>p$H_2$.

Explanation:

• The rate of diffusion is inversely proportional to partial pressure. It means that if the rate of diffusion is high the partial pressure of the gas will be more.
• The rate of diffusion of three gases such as $SO_2$, $CH_4$ and $H_2$ is calculated using the following formula:

Rate of diffusion = $\frac{1}{\sqrt{Molecular mass} }$

• As per the formula, the rate of diffusion for the given gases are as follows:

1. $H_2$ = 1
2. $CH_4$ = 0.25
3. $SO_2$ = 0.125

• From the above values, the order of rate of diffusion is $H_2>CH_4>SO_2$.
• As mentioned earlier, the rate of diffusion is inversely proportional to partial pressure, the order of partial pressure will p$SO_2$>p$CH_4$>p$H_2$.

Learn more about such concept

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