0.5 mole of each of H2, SO2, CH4, C2H6 and N2 are kept in a container. A hole was made in the container. After 3 hours the partial pressure of CH4 is 0.02 atm. How many gases have partial pressure greater than CH4 in the container.
Answers
Answer:
Pso>PCH>Pas
Explanation:
SO Molar' mass= 32 +32 64g/mol
CH4 Molar mass= 12 +4= 16g/mol
H Molar mass=2x 1 = 2g/mol
Rate of diffiusion is inversely related to molecular weight. Lighter the gas, more
is the diffiusion. The rate of diffiusion is given by,
THICHIsO
Hence the order of partial pressure will be
Pso>PCH>Pas
The ideal gas behaviour allows for the simple specification of gas mixtures. The ideal gas law, in particular, holds for each component of the mixture separately. Each component exerts its own pressure, known as partial pressure.
The thermodynamic activity of gas molecules is measured by partial pressure. Gases diffuse and react in a gaseous mixture based on their partial pressures rather than concentrations. A gas's partial pressure is the force it exerts. The sum of the partial pressures in a gas mixture equals the overall pressure. When forecasting gas flow, partial friction is extremely important. Remember that gases in two connected regions tend to equalise their pressure.
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Answer:
The order of partial pressures in the container after 3 hours will be
Explanation:
Step 1: The rate of diffusion is inversely proportional to partial pressure. It means that if the rate of diffusion is high the partial pressure of the gas will be more.
Step 2: The rate of diffusion of three gases such as and is calculated using the following formula:
Rate of diffusion =
Step 3: As per the formula, the rate of diffusion for the given gases are as follows:
= 1
= 0.25
= 0.125
From the above values, the order of rate of diffusion is .
As mentioned earlier, the rate of diffusion is inversely proportional to partial pressure, the order of partial pressure will p>p>p.
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