Question

0.5 mole of gas at temp 300K expands isothermally from an initial volume of 2 L to final volume 6 L. What is work done by the gas?

Answer 1

Answer:

Step-by-step explanation:

Solution: (a) The work done in isothermal

expansion is W = nRTln

V/Vfi

Where n = 0.5, Vf

= 6L, Vi

= 2L

W = 0.5 mol

8 319 300 62K

.ln mol

K L/L

= 1.369 kJ.

(b) From the first law of thermodynamics,

the heat supplied in an isothermal process

is spent to do work an a system. Therefore,

Q = W = 1.369 kJ.

Explanation:

MARK BRAINLIEST