Question

0.5 mole of oxygen occupies_____ML volume at NTP?​

Answer 1

Answer:

22.4 LITRE

Explanation:

At NTP, 1 mole of oxygen occupies a volume of 22.4 L.

Hence, 1 L of oxygen at NTP \displaystyle =\dfrac {1}{22.4}=

22.4

1

mol.

The number of oxygen molecules \displaystyle =\dfrac {1}{22.4} \times 6.02 \times 10^{23}=

22.4

1

×6.02×10

23

\displaystyle =\dfrac {6.02 \times 10^{23}}{22.4}=

22.4

6.02×10

23