0.5 mole of sugar is dissolved in 450 ml of
water at 25°C. What is vapor pressure of this
solution, if vapor pressure of water is 18 mm
Hg at the same temperature?
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Answered by
1
Answer:
Explanation:
Number of moles of glucose =
180
20.0
=0.1111
Number of moles of water =
18
70
=3.89
Mole fraction of glucose =
0.1111+3.89
0.1111
=0.0278
The relative lowering in vapour pressure is equal to the mole fraction of solute.
P
0
P
0
−P
=X⟹
25.21
25.21−P
=0.0278
P=25.21−(25.21×0.0278)=24.5 torr
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