Chemistry, asked by DivyanshKarel, 5 months ago

0.5 moles of CaCO3 contains how many oxygen atoms

Answers

Answered by rsagnik437
3

Answer

9.033×10²³ atoms.

Explanation:-

We know that 3 moles of oxygen are present in 1 mole of CaCO₃.

Thus, number of moles of oxygen, present in 0.5 mole of CaCO₃ :-

= 3×0.5

= 1.5 moles

Thus, 1.5 moles of oxygen are there in 0.5 mole of CaCO₃.

Number of atoms :-

= No of moles × Avogadro Number

= 1.5×6.022×10²³

= 9.033×10²³ atoms

Thus, 0.5 mole of CaCO contains 9.033×10²³ atoms of oxygen.

Some Extra Information:-

• Molar mass of Calcium (Ca) = 40 g/mol

• Molar mass of Carbon (C) = 12 g/mol

• Molar mass of Oxygen (O) = 16 g/mol

Hence, molar mass of CaCO₃ :-

= 40 + 12 + 16×3

= 52 + 48

= 100 g/mol

Answered by Bryant50
0

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ለምን ይህን

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