0.5 moles of CaCO3 contains how many oxygen atoms
Answers
Answer
9.033×10²³ atoms.
Explanation:-
We know that 3 moles of oxygen are present in 1 mole of CaCO₃.
Thus, number of moles of oxygen, present in 0.5 mole of CaCO₃ :-
= 3×0.5
= 1.5 moles
Thus, 1.5 moles of oxygen are there in 0.5 mole of CaCO₃.
Number of atoms :-
= No of moles × Avogadro Number
= 1.5×6.022×10²³
= 9.033×10²³ atoms
Thus, 0.5 mole of CaCO₃ contains 9.033×10²³ atoms of oxygen.
Some Extra Information:-
• Molar mass of Calcium (Ca) = 40 g/mol
• Molar mass of Carbon (C) = 12 g/mol
• Molar mass of Oxygen (O) = 16 g/mol
Hence, molar mass of CaCO₃ :-
= 40 + 12 + 16×3
= 52 + 48
= 100 g/mol
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