Question

0.56 g KoH is present in 100 ml of the solution what is the normality ?

a ) 1 N

B) 0.1 N

c) 2N

d)0.2 N

Answer 1

answer :-

normality = w / GEM × 100 / v(ml)

= 0.56 /56 × 1000 /10

= 0.1 N

option (B)

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Answer 2

Explanation:

0.56/ 56 × 1000/ 10

B = 0.1 N

so option B is the answer