Question

0.56 gm of gas occupies 280 cm^3 at NTP then its molecular mass is ​

Answer 1

Answer:

50

Explanation:

USE PV =NRT

P at NTP= 1atm

v = 280ml =0.28l

T = 298K

R=0.082

N = 0.56/M                         M=molar mass

Answer 2

HERE IS YOUR ANSWER____

*******____________******

22.4 L is occupied by 1 mole of a gas at STP.

So, 280 cm3 (0.280 L) will be occupied by (1/22.4) x 0.280 = 0.0125 mole

Mass of 0.0125 mole of the given gas = 0.56 g

Therefore, mass of 1 mole of the given gas = (0.56/0.0125) x 1 = 44.8 g

 

Hence, the molecular mass of the gas is 44.8 g

@HOPE IT HELPS YOU!!

Read more on Brainly.in - https://brainly.in/question/2979620#readmore