Question

0.58 g of hydrocarbon on combustion gave 0.9 g
water. The percentage of carbon is about:
(a) 75.8 (b) 82.76 (c) 27.85 (d) 68.8​

Answer 1

Answer:

82.75%

Explanation:

Mole of water formed =0.9/18=0.05,

so mole of hydrogen 0.05∗2=0.1

mass of hydrogen obtained =0.1∗1=0.1gm

So mass of carbon in hydrocarbon is 0.58−0.1=0.48 gm

% of carbon in hydrocarbon =(0.48/0.58)∗100=82.75 %