0.583g of acetone when vaporized formed 225 cm^3 of vapours at S.T.P. Calculate gram molecular mass of the gas [22.4 litres of any gas at STP =1 gram molecular mass of gas].
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= 1 g. mol. mass of gas] 22400 cm3 of acetone at stp will weigh = (0.583 * 22400) / 225 = 58.04 g
Explanation:
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