0.5g silver is dissolved in excess of nitric acid.This solution is treated with excess of NaCl solution when 0.66g of silver chloride is formed .One gram of metallic silver is heated in dry chlorine to give 1.32 g AgCl.Show that this data confirm the law of constant proportion
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28
Given that ,
In First Case:-
0.5g silver produce = 0.66g. of silver chloride
1g silver produce = 0.66/0.5= 1.3g. of silver chloride.
1g silver produce= 1.3 g of silver chloride.
so
..
In 2nd Case:-.
1g silver produce = 1.3 g gram of silver chloride..
Hence in both cases mass of silver chloride remain same !...
or
.#second method mentioned in picture!!..
Thus it shows that law of constant proportion is true!!!!...
In First Case:-
0.5g silver produce = 0.66g. of silver chloride
1g silver produce = 0.66/0.5= 1.3g. of silver chloride.
1g silver produce= 1.3 g of silver chloride.
so
..
In 2nd Case:-.
1g silver produce = 1.3 g gram of silver chloride..
Hence in both cases mass of silver chloride remain same !...
or
.#second method mentioned in picture!!..
Thus it shows that law of constant proportion is true!!!!...
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Refer to the attachment!!
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