Question

0.5i + 0.8j + Ck is a unit vector find the value of C

Answer 1

hello friend...!!

• According to the question,

0.5i + 0.8j + Ck is a unit vector , implies it's magnitude is equals to 1 therefore,

√(0.5)^2 + (0.8)^2 + c^2 = 1

0.25 + 0.64 + C^2 = 1

C^2 = 1 - 0.89

C^2 = 0.11

C = √0.11

therefore the value of C is √0.11

______________________________

Hope it helps...!!