Question

0.5x (2x² y² +1.5xy³)
Find the following products and then evaluate when x=2 and y=-1​

Answer 1

Answer:

Step-by-step explanation:

$(0.5)(2)(2(22)(12)+(1.5)(2)(13))(0.5)(2)(2(22)(12)+(1.5)(2)(13))=11$

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Answer 2

Answer:

(i) 2.5

(ii) 4

Step-by-step explanation:

(i) 0.5(2x²y²+1.5xy³) = 1.0x²y² + 0.75xy³

Now, put x= 2, y= -1

=> (2)²(-1)² + 0.75(2)(-1)³

=> 4 - 1.5 = 2.5

OR

(ii) If question is 0.5x(2x²y² + 1.5xy³),then

1.0x³y² + 0.75x²y³

put x= 2, y= -1

(2)³(-1)² + 0.75(2)²(-1)³

8 - 3 = 4