Question

0.6+0.7(bar in 7)+0.47(bar in 47) . p/ q form

class 9​

Answer 1

Answer:

$0.6 + 0.7bar + 0.47 bar\\ = \frac{6}{10} + \frac{7}{9} + \frac{47}{99} \\ = \frac{594 + 770 + 470}{990} \\ = \frac{1834}{990}$