Question

0.6 g of a gas at 15°C and 745 mm Hg occupies
200 cm. It occupies 182.6 cm in dry state at N.T.P.
Calculate the aqueous tension at 15°C.




plzz answer it immediately​

Answer 1

Answer:

Explanation:Given:

0.6 g of a gas at 15°C and 745 mm Hg occupies 200 3 cm . It occupies 182.6 3 cm in dry state at N.T.P.

To find:

Calculate the aqueous tension at 15°C.

Solution:

From given, we have,

P1 =  745 mmHg

V1 = 200 ml

P2 =?

V2= 182.6 cc

using Boyle's law, we have,

P1V1 = P2V2

where,

P1 and V1 = initial pressure and volume values

P2 and V2 = final pressure and volume values

substituting the given values in the above equation, we get,

P2 = 816 mmHg

Therefore,

Aqueous tension = P2 - P1

= 816 - 745 =  71 mmHg

∴ The aqueous tension at 15°C is 71 mmHg