Question

0.6 g of urea on strong heating with NaOH evolves NH3. Liberated NH3 will combine completely with which of the following HCl solution ?

Answer 1

100 mL of 0.2 N HCl is the Answer

Explanation:

• Urea Formula is $CH_4N_2O$

• Urea - A nitrogenous compound  

It has a carbonyl group with 2 amine groups and shows an activity called an osmotic diuretic.

• HCl also called Hydrochloric Acid.

2 $\times$ mole of Urea = mole of $NH_3$ ........(1)

One mole of $NH_3$= One Mole of HCl ........(2)

Therefore mole of HCl = 2 $\times$ mole of Urea  

= $2 \times (\frac {0.6}{60}) = 0.02 mol$

= $100 \times 0.2 \times 1$

= 0.02 mol,  from 1.

100 mL of 0.2 N HCl is the Answer