0.6. In Figure 1. XYIOR. 18 - -
(a) 27 cm
(21 cm
and PR - 63 cm, then YR equals:
(b) 189 cm
(4) 09 cm
Ans (): 27 cm
g. 1
Answers
Answer:
0.6. In Figure 1. XYIOR. 18 - -
(a) 27 cm
(21 cm
and PR - 63 cm, then YR equals:
(b) 189 cm
(4) 09 cm
Ans (): 27 cm
g. 10.6. In Figure 1. XYIOR. 18 - -
(a) 27 cm
(21 cm
and PR - 63 cm, then YR equals:
(b) 189 cm
(4) 09 cm
Ans (): 27 cm
g. 1Take a coloured paper, draw and cut a right-angled triangle ACB right-angled at C, of sides 3 cm, 4 cm and 5 cm as shown in fig. (i).
NCERT Class 10 Maths Lab Manual - Pythagoras Theorem 1
Paste this triangle on white sheet of paper.
Draw squares on each side of the triangle on side AB, BC and AC and name them accordingly as shown in figDraw a right angled Triangle of sides 3 cm, 4 cm and 5 cm. Make the squares sheets of 3 cm *3 cm, 4 cm * 4 cm and 5 cm * 5 cm. Fix these squares sheets to the sides of the triangle. Make the squares sheets of 3 cm * 3 cm such that the area should be 9 sq. cm.
Similarly repeat the same thing with the remaining squares sheets.
With this , We can prove the above theorem.
On the above You should consider a= 4 cm, b= 3 cm and c= 5 cm.In a right-angled triangle the square of hypotenuse is equal to the sum of squares on the other two sides.
Concept of a right-angled triangle.
Area of square = (side)2
Construction of perpendicular linesVolume of the store =2.5
3
=15.625 m
3
=15,625,000 cm
3
Volume of the cubic box =15625 cm
3
i) Number of boxes =
Volume of one box
Volume of the store
=
15625
15625000
=1000.
ii) Dimensions of the box =
3
Volume
=
3
15625
=25 cm.
So, the answer is [D].