Question

0.
6. In right ∆
PQR, right-angled at Q, PQ=5 cm and PR = 7 cm. Find the values of sin P,
cos P, sin R and cos R. Find the value of sin P-COS R.
​

Answer 1

Answer:

h²=p²+b²

7²=5²+b²

7²=25+b²

49-25=b²

24=b²

12=b

PQ=5cm

PR=7cm

sin P =p/h = 12/7

cos P = 5/12

sin R = 5/7

Cos R= 12/7

HERE IS YOUR ANSWER ''''''''''''

Answer 2

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