Question

0.6 mole of NHin a reaction vessel of 2dm capacity was brought to equilibrium. The vessel was then found to contain 0.15 mole of H formed by the reaction 2NH 3(g) = N2(g) + 3 H 2(g) [KCET 1999] Which of the following statements is true (a) 0.15 mole of the original NHhad dissociated at equilibrium (b)0.55 mole of ammonia is left in the vessel (c)At equilibrium the vessel contained 0.45 mole of N2 (d)The concentration of NHat equilibrium is 0.25 mole per dm

Answer 1

Answer: See Here

Explanation:

0.15 mole of the original NH3 had dissociated at equlibrium

0.55 mole of ammonia is left in the vessel

At equilibrium the vessel contained 0.45 mole of N2

The concentration of NH3 at equlibrium is 0.25 mole per