Question

0.6 mole of NHin a reaction vessel of 2dm capacity was brought to
equilibrium. The vessel was then found to contain 0.15 mole of H
formed by the reaction
2NH 3(g) = N2(g) + 3 H 2(g)
[KCET 1999]
Which of the following statements is true
(a) 0.15 mole of the original NHhad dissociated at equilibrium
(b)0.55 mole of ammonia is left in the vessel
(c)At equilibrium the vessel contained 0.45 mole of N2
(d)The concentration of NHat equilibrium is 0.25 mole per dm

Answer 1

Answer:

no more no 6 is equal to the mole of 0.5 is ammonium left in the vessel