Question

0.6
The simple interest on a certain sum at 5% per annum in 3 years is 600. Find the sum.
Ans.​

Answer 1

Answer:

please mark me brainliest

Step-by-step explanation:

⇒  Here, we have T=3years,R=5% and S.I.=Rs.600

⇒  S.I.=100P×R×T​

⇒  600=100P×5×3​

∴  P=5×3600×100​=Rs.4000.

⇒  Now, taking P=Rs.4000,T=3years and R=5%

⇒  A=P(1+100R​)T

⇒  A=4000×(1+1005​)3

⇒  A=4000×(2021​)3

⇒   A=80004000×9261​=Rs.4,630.50

Answer 2

${\blue{\bigstar}} \ {\underline{\green{\textsf{\textbf{Given :-}}}}}$

• Simple Interest = 600
• Rate of Interest = 5% per annum
• Time = 3 years

${\pink{\bigstar}} \ {\underline{\orange{\textsf{\textbf{To Find :-}}}}}$

• Principal

${\red{\bigstar}} \ {\underline{\purple{\textsf{\textbf{Formula Used :-}}}}}$

${\boxed{\green{\tt{S.I. = \dfrac{P \times R \times T}{100} }}}}$

where,

• S.I. = Simple Interest i.e. 600
• R = Rate of Interest i.e. 5% per annum
• T = Time i.e. 3 years
• P = Principal

${\orange{\bigstar}} \ {\underline{\blue{\textsf{\textbf{Solution :-}}}}}$

According to the question by using the formula of Simple Interest, we get,

${\sf{600 = \dfrac{P \times 5 \times 3}{100} }}$

After Transposing,

${:\implies} {\sf{P = \dfrac{600 \times 100}{5 \times 3} }}$

${:\implies} {\sf{P = \dfrac{60,000}{15} }}$

${:\implies} {\sf{P = \dfrac{{\cancel{60,000}}^{ \ 4000}}{{\cancel{15}}^{ \ 1}} }}$

${:\implies} {\sf{P = 4,000}}$

${\blue{\textsf{\textbf{Principal = Rs. 4,000}}}}$

${\boxed{\pink{\textsf{\textbf{Hence, the sum is Rs. 4,000}}}}}$

${\large{\green{\checkmark}}} \ {\underline{\orange{\textsf{\textbf{Verification:-}}}}}$

${:\implies} {\sf{4,000 = \dfrac{600 \times 100}{5 \times 3} }}$

${:\implies} {\sf{4,000 = \dfrac{60,000}{15} }}$

${:\implies} {\sf{4,000 = \dfrac{{\cancel{60,000}}^{ \ 4000}}{{\cancel{15}}^{ \ 1}} }}$

${:\implies} {\sf{4,000 = 4,000}}$

${\pink{\Longrightarrow}} \ {\green{\textbf{\textsf{LHS = RHS}}}} \ {\pink{\Longleftarrow}}$

${\sf{Hence, Verified}} \ {\large{\green{\checkmark}}}$