0.62X4
t)
Calculate the % of carbon present in glucose (C6H1206).
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Answers
Answered by
1
40%
Explanation:
[72÷(72+12+96)]× 100%=40%
Answered by
1
Answer:
0.25%
Explanation:
% of carbon=no.of carbon atoms÷Total no.of atoms
=6÷24
=0.25
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