Question

0.63 g of dibasic acid was dissolved in water. The volume of the solution was made 100 mL. 20mL of this acid
solution required 10 mL N/5 NaOH solution. What is the molecular mass of the acid?
(1) 63
(2) 126
(3) 252
(4) 128​

Answer 1

Answer:

126.

Explanation:

(Acid)N1​V1​​≡(NaOH)N2​V2​​

N1​×20=51​×10

N1​=51​×2010​=101​

Strength of the acid solution = Eq. mass of the acid ×Normality

=E×101​=10E​g/L

Mass of acid in 100 mL of the solution =0.63 (given)

So, 100E​=0.63 or E=63

Mol. mass =Basicity×Eq.mass

=2×63=126.

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