Question

0.63 gram oxalic acid(equivalent weight=63)is dissolved in250ml of solution.find out the normality of solution

Answer 1

✪Answer :-

0.04 equivalent/lit

✪Given :-

• Weight of oxalic acid is 0.63 g
• Equivalent weight is 63
• Volume is 250 ml

✪To find :-

• Normality of the solution

✪Solution:-

For finding the normality we have formula that is

✪N = w/GEW × 1000/v

where ,

• w = given weight
• GEW = Gram equivalent weight
• v = volume

✪Substituting the values ,

N = 0.63/ 63 × 1000/250

N = 0.63/63 × 4

N = 0.01 × 4

✪N = 0.04 equivalent/lit

So, the normality of a given solution is 0.04 equivalent/lit

✪Know more :-

Normality (N) :- The number of gram equivalents of the solute present in one litre of solution is known as normality

Units of Normality are :- equivalent/lit

✪It depends on temperature

✪Normality of the solution decreases with increase of temperature, since volume of solution is directly proportional to temperature