Question

0.63 gram oxalic acid is dissolved in 250 ml of solution. Find out the normality of solution

Answer 1

Answer:

hey buddy here is your answer

Explanation:

GIVEN,

m=0.63g

Equal.wt.=63

volume=250/1000L

=1/4L

NORMALITY{N}=m/eq.wt.*vol.

=6310.63*(1/4)

=0.04N

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