Question

0.635 g of a cupric salt was dissolved in water, excess of KI was added and the liberated iodine required 25
ml of N/5 Na, S, O, solution the weight percentage of copper in the salt is
(1) 25%
(2) 40%
(3) 50%
(4) 63.5%

Answer 1

Answer:

I don't know

u don't know

Explanation:

so how can be explaine

Answer 2

The weight percentage of copper in the salt is 50%

Explanation:

The number of Cu²⁺ = 25 × 1/5 = 5 = Number of milli moles

The weight of the copper in cupric salt is:

⇒ 5 × 63.5 × 10⁻³ = 0.3175 g

Now, the weight of the copper in 0.635 g of a cupric salt is:

⇒ 0.3175/0.635 = 0.5 g

now, the weight percentage is:

⇒ 0.5 × 100% = 50%