0.64*0.64+2*0.64*0.36+0.36*0.36,using identities
Answers
Answer:
0.64*0.64+2*0.64*0.36+0.36*0.36 = 1
Step-by-step explanation:
Let 0.64 = a
and 0.36 = b
We need to solve the given question using identities.
We know that (a + b)² = a² + b² + 2ab --(i)
As we have already assumed the values of 0.64 and 0.36,
Substituting the same in the given question, we get,
0.64*0.64+2*0.64*0.36+0.36*0.36 = a *a + 2 * a * b + b * b
= a² + 2ab + b²
= (a + b)² (from equation i)
= (0.64 + 0.36)²
= (1.00)²
= 1
Hence, 0.64*0.64+2*0.64*0.36+0.36*0.36 = 1
Step-by-step explanation:
please see at the attached picture above
