0.65 g of a metal when treated with dim.sulphuric acid liberated224ml of dry hydrogen at stp .the equivalent mass of metal is
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sorry dil.sulphuric acid
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Equivalent mass of the metal = Mass of the metalVol of H2 displaced at STP × 11200 = 0.134.2 × 11200 =32.75 g
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Equivalent mass of the metal = Mass of the metalVol of H2 displaced at STP × 11200 = 0.134.2 × 11200 =32.75 g
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Answer:
w1=0.65g
w2=2/22400*224=0.02g
equivalent weight of the metal=w1/w2
=0.65/0.02=32.5.
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