Question

0.66 g of H3PO2 will require 'X' ml of 0.1 M NaOH for complete neutralisation. Then x =

Answer 1

The value of x is 1000 mL.

Explanation:

The chemical reaction follower in neutralization of H₃PO₂ is:

H₃PO₂ + NaOH → NaH₂PO₂

The equivalent weight is given by the formula:

Equivalent weight = (Weight of acid)/(Normality × Volume)

Since, Equivalent weight = Molar mass

The molar mass of H₃PO₂ = 66

Weight of acid = 0.66 g

Normality = 0.1 M

Volume = x

66 = (0.66)/(0.1 × x)

0.1 × x = 0.66/66 = 0.01

x = 0.01/0.1 = 0.1 L

∴ X = 1000 mL

Answer 2

Answer:

See the attachment

Explanation:

My answer is right