Question

0.67 kg of gas at 14 bar and 290°C is expanded to four times the original volume according to the law PV1.3=constant. Calculate: (1) The original and final volume of the gas (2) The final temperature of the gas (3) The final pressure of the gas. Take R=287 J/kg K.​

Answer 1

Given : P=200,000 Pa V

i

=1.0 m

3

V

f

=2.0 m

3

Work done by gas during expansion W=P(V

f

−V

i

)=200000×(2.0−1.0)=200,000 J

Amount of heat absorbed by the gas Q=+100,000 J

Using Q=ΔU+W

∴ 100000=ΔU+200000 ⟹ΔU=−100,000 J

Answer 2

Answer:

100,000 J

Explanation:

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