Question

0.7 g of iron combines directly with 0.4 g ofsulphur to form ferrous sulphide. If 2.8 g of iron are dissolved in dilute HCI & excess ofsodium sulphide solution is added, 4.4g. of iron sulphide are precipitated. Does thedata illustrated the law of constant
composition?

#Please ans ​

Answer 1

Hello dear!

According to law of constant composition a pure  chemical compound contains the same elements in the fixed  proportion of their weights regardless the mode of preparation.

In the first line, the ratio of weights (R₁) of iron(Fe) and sulphur(S) will be:

Fe : S : : 0.7 : 0.4

Fe : S : : 7 : 4

∵  2.8 g of iron gives 4.4 g ferrous sulphide precipitate.

So,  Amount of sulphur combines with 2.8 g iron  = 4.4 - 2.8 = 1.6 g.

Now,

The ratio of weights will be: (R₂)

Fe : S : : 2.8 : 1.6

Fe : S : : 7 : 4

∵ R₁ = R₂ (The ratio of two elements in both the compounds is equal).

Hence, It follows the law of constant composition.

Answer 2

Solution in the attachment

Mark this answer as a branlieast