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Let a particle moving in a
Orole of radius 2m with its
speed increasing at a rate
2m/sAt an instant speed
of the particle is 2 m/s then
its net acceleration will be
22m
Answers
Answered by
0
Answer:
Explanation:
Linear speed of particle at t=2s is
v=(2)
2
=4m/s
∴ Radial acceleration
a
r
=
r
v
2
=
2
(4)
2
=8m/s
2
The tangential acceleration is a
t
=
DT
DV
=2t
∴ Tangential acceleration at t=2s is
a
t
=(2)(2)=4m/s
2
∴ Net acceleration of particle t=2s is
a=
(a
r
)
2
+(a
t
)
2
=
(8)
2
+(4)
2
or a=
80
m/s
2
Note: On any curved path (not necessarily a circular one) the acceleration of the particle has two components a
t
anda
n
in two mutually perpendicular directions. Component of
a
along
v
is a
t
and perpendicular to
v
isa
n
. Thus,
∣
a
∣=
a
t
2
+a
n
2
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