0.72) A bulb whose resistance is 10ohm is connected to a 6Vbattery. Calculate (a) the
current through the circuit(b) the potential difference across the bulb.
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Answer:
I=0.6 Amp
V=6 v
Explanation:
Using Ohm's law
I=V/R =6/10 =0.6 Amp
As there is no other resistance in circuit so potential difference across the bulb is same is that of emf of battery =6 V
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