0.74g Ca(OH)2 is dissolved in water to give 200ml solution at 298K. The hydrogen ion concentration in the solution is :
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given, 0.74g Ca(OH)2 is dissolved in water to give 200mL solution at 298K.
mass of Ca(OH)2 = 0.74g
molar mass of Ca(OH)2 = 40 + (16 + 1) × 2
= 40 + 34 = 74g/mol
so, number of moleof Ca(OH)2 = 0.74/74 =0.01
now, molarity = number of moles of Ca(OH)2/volume of solution in L
= {0.01/200} × 1000 = 0.05M
Ca(OH)2 dissociate ,
so, concentration of Ca(OH)2 = 2 × concentration of [OH-]
= 0.05 × 2 = 0.1M
we know ,
= 10^-14/0.1 = 10^-13 M
hence, concentration of hydrogen ion is 10^-13M
might help u dude
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