Question

0.783 of copper is deposited by passing 25 ampere current through the copper sulphate solution for 1 hour. find the vacancy of copper . (A= 63)

Answer 1

Explanation:

Formula→W=ξIt

where W=Mass, I=Current, t=Time, ξ=ElectrochemicalEquivalent

ξ=

Faraday(F)

EquivalentWeight(E)

.

∴W=

F

E

×I×t.

∴E=

I×t

W×F

=

0.25×3600

0.295×96500

E=31.63