0.83×0.83×0.83+0.17×0.17×0.17÷0.83×0.83-0.83×0.17+0.17×0.17
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Given: The expression 0.83×0.83×0.83+0.17×0.17×0.17÷0.83×0.83-0.83×0.17+0.17×0.17
To find: The final value?
Solution:
- Now we have given the term : 0.83×0.83×0.83+0.17×0.17×0.17÷0.83×0.83-0.83×0.17+0.17×0.17.
- Let this term be denoted as S.
- So:
S = 0.83×0.83×0.83+0.17×0.17×0.17÷0.83×0.83-0.83×0.17+0.17×0.17
- Now solving this we get:
S = 0.83×0.83×0.83 + 0.17×0.17×0.17 / 0.83×0.83 - 0.83×0.17 + 0.17×0.17
S = (0.83)³ + (0.17)³ / (0.83)² - 0.83×0.17 + (0.17)²
- Now we know the formula for a^3 + b^3 = (a+b)(a^2-ab+b^2)
- So applying this, we get:
S = ( 0.83+0.17 ) x (0.83)² - 0.83×0.17 + (0.17)² / (0.83)² - 0.83×0.17 + (0.17)²
- So cancelling the common terms, we get:
S = ( 0.83+0.17 )
S = 1.00
Answer:
So the value of the given term is 1.
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