Biology, asked by pankajjaokar9881, 1 year ago

0.9% of NaCl solution is considered isotonic for RBCs.If RBCs are placed in 2% NaCl solution ,what will happen to the cells? What is such a solution called?

Answers

Answered by rimamariya2006
41

Answer:

a red blood cell has a concentration of about 0.9% NaCl. if you put it in a 0.9% NaCl solution, it would be considered an isotonic solution and nothing would happen. a 0.1% NaCl solution would be hypotonic (less concentrated) and water would flow into the cell, causing it to swell and possibly burst.

Explanation:

here is ur ans....

Answered by BRAINLIESTF
19

the cell would shrink

Explanation:

In this case, the concentration of solution outside the blood cell is more and is thus called hypertonic. It infers that the cell will shrink, as the water inside the cell moves outside making the cell flaccid. This process is called exosmosis. It happens because of the variation in the concentration gradient.

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