0.98 gram of the metal sulphate was dissolved in water and excess of barium chloride was added. The precipitated barium sulphate weighed 0.95 gram. Calculate the equivalent weight of the metal.
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Answered by
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hey friend !!!!
your answer is "0.59"
Explaination
____________
Barium sulphate mol wt = 233.43
Molecular Weight of SO4= 32 +16(4) = 32+64 = 96
= 96/233.43 = 41.1
Weight of SO4 in 0.95 g =
41.1×0.95/100 = 0.39
so metal weight = 0.98-0.39 = 0.59
hope it will help you..
your answer is "0.59"
Explaination
____________
Barium sulphate mol wt = 233.43
Molecular Weight of SO4= 32 +16(4) = 32+64 = 96
= 96/233.43 = 41.1
Weight of SO4 in 0.95 g =
41.1×0.95/100 = 0.39
so metal weight = 0.98-0.39 = 0.59
hope it will help you..
arkapratim:
I wanted equivalent weight.
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0
Explanation:
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