0.9g of al realcts with dil.hcl to give h2 the volume of h2 evolved at stp is
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So 1/30 multiplied 3 H2 give 1/10 mole . So volume will be 22.4 x 1/10 = 2.24 L. Now given 0.9g of aluminum. Therefore moles of aluminum =0.9/27=1/30
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Answer:
1.12 L is the right answer.
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