Question

0.9x+y)(0.9x-y)=0.81x^(2)-y^(2)

Answer 1

Answer:

$\large{True} \\ (0.9x +y)(0.9x - y) = 0.81 {x}^{2} - {y}^{2}$

Step-by-step explanation:

$(0.9x + y)(0.9x - y) \\ = 0.81 {x}^{2} - 0.9xy + 0.9xy - {y}^{2} \\ \large {\boxed {= { \underline{ \underline{0.81 {x}^{2} - {y}^{2} }}}}}$