Question

0 A 0.4 kg ball traveling with the speed of 15 m s' strikes a rigid wall and
rebounds elastically. If the ball is in contact with the wall for 0.045 s, what
is (a) the momentum imparted to the wall and (b) the average force
exerted on the wall?
(12 kg m s', 266.7 N)
​

Answer 1

Explanation:

data:

m=0.4kg

v=15ms-1

p=?

formula: p=mv

p=(0.4)(15)

p=6

they are in opposite in direction

so it will -6

vf-vi

-6-6

p=12kgms-1

momentum = (F)(t)

12=F (0.045)

F=12/0.045

F=266.6666667 N