Math, asked by ex12345678901345, 1 month ago

(0)(a + bla
One of the factor of X6 + 10x3 - 27 is
(a) x2 - X + 3
(x²-x-3
(c) x2 + x - 3
(d) x2 + x + 3
One of the factor of x® + 10x2-271RAVAT​

Answers

Answered by vikashpatnaik2009
1

Answer:

Given, x  

6

−10x  

3

−27

=x  

6

−x  

3

−27−9x  

3

 

=(x  

2

)  

3

+(−x)  

3

+(−3)  

3

−3(x  

2

)(−x)(−3)

Using, a  

3

+b  

3

+c  

3

−3abc=(a+b+c)(a  

2

+b  

2

+c  

2

−ab−ac−bc)

=(x  

2

−x−3)((x  

2

)  

2

+(−x)  

2

+(−3)  

2

−(x  

2

)(−x)−(x  

2

)(−3)−(−x)(−3))

=(x  

2

−x−3)(x  

4

+x  

2

+9+x  

3

+3x  

2

−3x)

=(x  

2

−x−3)(x  

4

+x  

3

+4x  

2

−3x+9)

Answered by sanjaylond985
1

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